-2(4y-3)-y=-3(y-5)

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Solution for -2(4y-3)-y=-3(y-5) equation: 



-2(4y-3)-y=-3(y-5)

We move all terms to the left:

-2(4y-3)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-2(4y-3)-(-3(y-5))=0

We multiply parentheses

-1y-8y-(-3(y-5))+6=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

-9y-(-3y+15)+6=0

We get rid of parentheses

-9y+3y-15+6=0

We add all the numbers together, and all the variables

-6y-9=0

We move all terms containing y to the left, all other terms to the right

-6y=9

y=9/-6

y=-1+1/2

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