4(3x-3)=3(2x+9+19)

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Solution for 4(3x-3)=3(2x+9+19) equation: 



4(3x-3)=3(2x+9+19)

We move all terms to the left:

4(3x-3)-(3(2x+9+19))=0

We add all the numbers together, and all the variables

4(3x-3)-(3(2x+28))=0

We multiply parentheses

12x-(3(2x+28))-12=0



We calculate terms in parentheses: -(3(2x+28)), so:

3(2x+28)

We multiply parentheses

6x+84

Back to the equation:

-(6x+84)



We get rid of parentheses

12x-6x-84-12=0

We add all the numbers together, and all the variables

6x-96=0

We move all terms containing x to the left, all other terms to the right

6x=96

x=96/6

x=16

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