-2(3z+8)=1/3)9-18z)

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Solution for -2(3z+8)=1/3)9-18z) equation: 



-2(3z+8)=1/3)9-18z)

We move all terms to the left:

-2(3z+8)-(1/3)9-18z))=0

We add all the numbers together, and all the variables

-2(3z+8)-18z))-(+1/3)9=0

We multiply parentheses

-6z-18z))-(+1/3)9-16=0

We multiply all the terms by the denominator


-6z*3)9-16-18z))-(+1=0

Wy multiply elements

-18z^2=0

a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{-36}=0$

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