4(6/5)x+9x=2116

Solution for 4(6/5)x+9x=2116 equation:

4(6/5)x+9x=2116

We move all terms to the left:

4(6/5)x+9x-(2116)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4(+6/5)x+9x-2116=0

We add all the numbers together, and all the variables

9x+4(+6/5)x-2116=0

We multiply parentheses

24x^2+9x-2116=0

a = 24; b = 9; c = -2116;
Δ = b2-4ac
Δ = 92-4·24·(-2116)
Δ = 203217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{203217}}{2*24}=\frac{-9-\sqrt{203217}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{203217}}{2*24}=\frac{-9+\sqrt{203217}}{48}
$