-2(3z+5)=5(-2z+6)

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Solution for -2(3z+5)=5(-2z+6) equation: 



-2(3z+5)=5(-2z+6)

We move all terms to the left:

-2(3z+5)-(5(-2z+6))=0

We multiply parentheses

-6z-(5(-2z+6))-10=0



We calculate terms in parentheses: -(5(-2z+6)), so:

5(-2z+6)

We multiply parentheses

-10z+30

Back to the equation:

-(-10z+30)



We get rid of parentheses

-6z+10z-30-10=0

We add all the numbers together, and all the variables

4z-40=0

We move all terms containing z to the left, all other terms to the right

4z=40

z=40/4

z=10

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