2(2x+3)=3(6+x)

Solution for 2(2x+3)=3(6+x) equation:

2(2x+3)=3(6+x)

We move all terms to the left:

2(2x+3)-(3(6+x))=0

We add all the numbers together, and all the variables

2(2x+3)-(3(x+6))=0

We multiply parentheses

4x-(3(x+6))+6=0


We calculate terms in parentheses: -(3(x+6)), so:

3(x+6)

We multiply parentheses

3x+18

Back to the equation:

-(3x+18)


We get rid of parentheses

4x-3x-18+6=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12