-2(3y-5)=2(y+9)

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Solution for -2(3y-5)=2(y+9) equation: 



-2(3y-5)=2(y+9)

We move all terms to the left:

-2(3y-5)-(2(y+9))=0

We multiply parentheses

-6y-(2(y+9))+10=0



We calculate terms in parentheses: -(2(y+9)), so:

2(y+9)

We multiply parentheses

2y+18

Back to the equation:

-(2y+18)



We get rid of parentheses

-6y-2y-18+10=0

We add all the numbers together, and all the variables

-8y-8=0

We move all terms containing y to the left, all other terms to the right

-8y=8

y=8/-8

y=-1

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