5(2-4x)4x=10

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Solution for 5(2-4x)4x=10 equation: 



5(2-4x)4x=10

We move all terms to the left:

5(2-4x)4x-(10)=0

We add all the numbers together, and all the variables

5(-4x+2)4x-10=0

We multiply parentheses

-80x^2+40x-10=0

a = -80; b = 40; c = -10;
Δ = b2-4ac
Δ = 402-4·(-80)·(-10)
Δ = -1600
Delta is less than zero, so there is no solution for the equation

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