-2(3y+5)=-5(2y-2)+4y

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Solution for -2(3y+5)=-5(2y-2)+4y equation: 



-2(3y+5)=-5(2y-2)+4y

We move all terms to the left:

-2(3y+5)-(-5(2y-2)+4y)=0

We multiply parentheses

-6y-(-5(2y-2)+4y)-10=0



We calculate terms in parentheses: -(-5(2y-2)+4y), so:

-5(2y-2)+4y

We add all the numbers together, and all the variables

4y-5(2y-2)

We multiply parentheses

4y-10y+10

We add all the numbers together, and all the variables

-6y+10

Back to the equation:

-(-6y+10)



We get rid of parentheses

-6y+6y-10-10=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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