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2(x-3)+5=4-5(2x-1)
We move all terms to the left:
2(x-3)+5-(4-5(2x-1))=0
We multiply parentheses
2x-(4-5(2x-1))-6+5=0
We calculate terms in parentheses: -(4-5(2x-1)), so:We add all the numbers together, and all the variables
4-5(2x-1)
determiningTheFunctionDomain -5(2x-1)+4
We multiply parentheses
-10x+5+4
We add all the numbers together, and all the variables
-10x+9
Back to the equation:
-(-10x+9)
2x-(-10x+9)-1=0
We get rid of parentheses
2x+10x-9-1=0
We add all the numbers together, and all the variables
12x-10=0
We move all terms containing x to the left, all other terms to the right
12x=10
x=10/12
x=5/6
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