-2(3w-1)+w=4(w+2)

Solution for -2(3w-1)+w=4(w+2) equation:

-2(3w-1)+w=4(w+2)

We move all terms to the left:

-2(3w-1)+w-(4(w+2))=0

We add all the numbers together, and all the variables

w-2(3w-1)-(4(w+2))=0

We multiply parentheses

w-6w-(4(w+2))+2=0


We calculate terms in parentheses: -(4(w+2)), so:

4(w+2)

We multiply parentheses

4w+8

Back to the equation:

-(4w+8)


We add all the numbers together, and all the variables

-5w-(4w+8)+2=0

We get rid of parentheses

-5w-4w-8+2=0

We add all the numbers together, and all the variables

-9w-6=0

We move all terms containing w to the left, all other terms to the right

-9w=6

w=6/-9

w=-2/3