4=4(v+4)+2v

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Solution for 4=4(v+4)+2v equation: 



4=4(v+4)+2v

We move all terms to the left:

4-(4(v+4)+2v)=0



We calculate terms in parentheses: -(4(v+4)+2v), so:

4(v+4)+2v

We add all the numbers together, and all the variables

2v+4(v+4)

We multiply parentheses

2v+4v+16

We add all the numbers together, and all the variables

6v+16

Back to the equation:

-(6v+16)



We get rid of parentheses

-6v-16+4=0

We add all the numbers together, and all the variables

-6v-12=0

We move all terms containing v to the left, all other terms to the right

-6v=12

v=12/-6

v=-2

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