-2(3v-7)+8v=6+4(4v-1)

Solution for -2(3v-7)+8v=6+4(4v-1) equation:

-2(3v-7)+8v=6+4(4v-1)

We move all terms to the left:

-2(3v-7)+8v-(6+4(4v-1))=0

We add all the numbers together, and all the variables

8v-2(3v-7)-(6+4(4v-1))=0

We multiply parentheses

8v-6v-(6+4(4v-1))+14=0


We calculate terms in parentheses: -(6+4(4v-1)), so:

6+4(4v-1)

determiningTheFunctionDomain
4(4v-1)+6

We multiply parentheses

16v-4+6

We add all the numbers together, and all the variables

16v+2

Back to the equation:

-(16v+2)


We add all the numbers together, and all the variables

2v-(16v+2)+14=0

We get rid of parentheses

2v-16v-2+14=0

We add all the numbers together, and all the variables

-14v+12=0

We move all terms containing v to the left, all other terms to the right

-14v=-12

v=-12/-14

v=6/7