(x-1)-8=4(1+x)+5

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Solution for (x-1)-8=4(1+x)+5 equation: 



(x-1)-8=4(1+x)+5

We move all terms to the left:

(x-1)-8-(4(1+x)+5)=0

We add all the numbers together, and all the variables

(x-1)-(4(x+1)+5)-8=0

We get rid of parentheses

x-(4(x+1)+5)-1-8=0



We calculate terms in parentheses: -(4(x+1)+5), so:

4(x+1)+5

We multiply parentheses

4x+4+5

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

x-(4x+9)-9=0

We get rid of parentheses

x-4x-9-9=0

We add all the numbers together, and all the variables

-3x-18=0

We move all terms containing x to the left, all other terms to the right

-3x=18

x=18/-3

x=-6

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