-2(3t-1)=3(1-3t)-13

Solution for -2(3t-1)=3(1-3t)-13 equation:

-2(3t-1)=3(1-3t)-13

We move all terms to the left:

-2(3t-1)-(3(1-3t)-13)=0

We add all the numbers together, and all the variables

-2(3t-1)-(3(-3t+1)-13)=0

We multiply parentheses

-6t-(3(-3t+1)-13)+2=0


We calculate terms in parentheses: -(3(-3t+1)-13), so:

3(-3t+1)-13

We multiply parentheses

-9t+3-13

We add all the numbers together, and all the variables

-9t-10

Back to the equation:

-(-9t-10)


We get rid of parentheses

-6t+9t+10+2=0

We add all the numbers together, and all the variables

3t+12=0

We move all terms containing t to the left, all other terms to the right

3t=-12

t=-12/3

t=-4