-3v+41=2(v-2)

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Solution for -3v+41=2(v-2) equation: 



-3v+41=2(v-2)

We move all terms to the left:

-3v+41-(2(v-2))=0



We calculate terms in parentheses: -(2(v-2)), so:

2(v-2)

We multiply parentheses

2v-4

Back to the equation:

-(2v-4)



We get rid of parentheses

-3v-2v+4+41=0

We add all the numbers together, and all the variables

-5v+45=0

We move all terms containing v to the left, all other terms to the right

-5v=-45

v=-45/-5

v=+9

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