-2(3r-3)=3r+12(r+11)

Solution for -2(3r-3)=3r+12(r+11) equation:

-2(3r-3)=3r+12(r+11)

We move all terms to the left:

-2(3r-3)-(3r+12(r+11))=0

We multiply parentheses

-6r-(3r+12(r+11))+6=0


We calculate terms in parentheses: -(3r+12(r+11)), so:

3r+12(r+11)

We multiply parentheses

3r+12r+132

We add all the numbers together, and all the variables

15r+132

Back to the equation:

-(15r+132)


We get rid of parentheses

-6r-15r-132+6=0

We add all the numbers together, and all the variables

-21r-126=0

We move all terms containing r to the left, all other terms to the right

-21r=126

r=126/-21

r=-6