5(y+2)=-2(5y-2)+7y

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Solution for 5(y+2)=-2(5y-2)+7y equation: 



5(y+2)=-2(5y-2)+7y

We move all terms to the left:

5(y+2)-(-2(5y-2)+7y)=0

We multiply parentheses

5y-(-2(5y-2)+7y)+10=0



We calculate terms in parentheses: -(-2(5y-2)+7y), so:

-2(5y-2)+7y

We add all the numbers together, and all the variables

7y-2(5y-2)

We multiply parentheses

7y-10y+4

We add all the numbers together, and all the variables

-3y+4

Back to the equation:

-(-3y+4)



We get rid of parentheses

5y+3y-4+10=0

We add all the numbers together, and all the variables

8y+6=0

We move all terms containing y to the left, all other terms to the right

8y=-6

y=-6/8

y=-3/4

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