-2(3n-2)-(6n-5)=3(2n+(4-n)

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Solution for -2(3n-2)-(6n-5)=3(2n+(4-n) equation: 



-2(3n-2)-(6n-5)=3(2n+(4-n)

We move all terms to the left:

-2(3n-2)-(6n-5)-(3(2n+(4-n))=0

We add all the numbers together, and all the variables

-2(3n-2)-(6n-5)-(3(2n+(-1n+4))=0

We multiply parentheses

-6n-(6n-5)-(3(2n+(-1n+4))+4=0

We get rid of parentheses

-6n-6n-(3(2n+(-1n+4))+4+5=0

We add all the numbers together, and all the variables

-12n-(3(2n+(-1n+4))+4+5=0

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