2(f+3)=19

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Solution for 2(f+3)=19 equation: 



2(f+3)=19

We move all terms to the left:

2(f+3)-(19)=0

We multiply parentheses

2f+6-19=0

We add all the numbers together, and all the variables

2f-13=0

We move all terms containing f to the left, all other terms to the right

2f=13

f=13/2

f=6+1/2

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