-2(3/2m-4)=(4-2m)+3m

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Solution for -2(3/2m-4)=(4-2m)+3m equation: 



-2(3/2m-4)=(4-2m)+3m

We move all terms to the left:

-2(3/2m-4)-((4-2m)+3m)=0



Domain of the equation: 2m-4)!=0

m∈R



We add all the numbers together, and all the variables

-2(3/2m-4)-((-2m+4)+3m)=0

We multiply parentheses

-6m-((-2m+4)+3m)+8=0



We calculate terms in parentheses: -((-2m+4)+3m), so:

(-2m+4)+3m

We add all the numbers together, and all the variables

3m+(-2m+4)

We get rid of parentheses

3m-2m+4

We add all the numbers together, and all the variables

m+4

Back to the equation:

-(m+4)



We get rid of parentheses

-6m-m-4+8=0

We add all the numbers together, and all the variables

-7m+4=0

We move all terms containing m to the left, all other terms to the right

-7m=-4

m=-4/-7

m=4/7

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