6(2+x)=9(3-x)

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Solution for 6(2+x)=9(3-x) equation:



6(2+x)=9(3-x)
We move all terms to the left:
6(2+x)-(9(3-x))=0
We add all the numbers together, and all the variables
6(x+2)-(9(-1x+3))=0
We multiply parentheses
6x-(9(-1x+3))+12=0
We calculate terms in parentheses: -(9(-1x+3)), so:
9(-1x+3)
We multiply parentheses
-9x+27
Back to the equation:
-(-9x+27)
We get rid of parentheses
6x+9x-27+12=0
We add all the numbers together, and all the variables
15x-15=0
We move all terms containing x to the left, all other terms to the right
15x=15
x=15/15
x=1

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