-2(3-4z)+72=13z-4

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Solution for -2(3-4z)+72=13z-4 equation: 



-2(3-4z)+72=13z-4

We move all terms to the left:

-2(3-4z)+72-(13z-4)=0

We add all the numbers together, and all the variables

-2(-4z+3)-(13z-4)+72=0

We multiply parentheses

8z-(13z-4)-6+72=0

We get rid of parentheses

8z-13z+4-6+72=0

We add all the numbers together, and all the variables

-5z+70=0

We move all terms containing z to the left, all other terms to the right

-5z=-70

z=-70/-5

z=+14

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