(3/4)(6x+1)-3x=(1/4)(2x-1)

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Solution for (3/4)(6x+1)-3x=(1/4)(2x-1) equation: 



(3/4)(6x+1)-3x=(1/4)(2x-1)

We move all terms to the left:

(3/4)(6x+1)-3x-((1/4)(2x-1))=0



Domain of the equation: 4)(6x+1)!=0

x∈R





Domain of the equation: 4)(2x-1))!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)(6x+1)-3x-((+1/4)(2x-1))=0

We add all the numbers together, and all the variables

-3x+(+3/4)(6x+1)-((+1/4)(2x-1))=0

We multiply parentheses ..

(+18x^2+3/4*1)-3x-((+1/4)(2x-1))=0

We calculate fractions


((+18x^2+3*4)(2x-1)))/16x^2+()/16x^2-3x=0

We can not solve this equation

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