-2(3-2z)=4(1-z)

Solution for -2(3-2z)=4(1-z) equation:

-2(3-2z)=4(1-z)

We move all terms to the left:

-2(3-2z)-(4(1-z))=0

We add all the numbers together, and all the variables

-2(-2z+3)-(4(-1z+1))=0

We multiply parentheses

4z-(4(-1z+1))-6=0


We calculate terms in parentheses: -(4(-1z+1)), so:

4(-1z+1)

We multiply parentheses

-4z+4

Back to the equation:

-(-4z+4)


We get rid of parentheses

4z+4z-4-6=0

We add all the numbers together, and all the variables

8z-10=0

We move all terms containing z to the left, all other terms to the right

8z=10

z=10/8

z=1+1/4