5(t-3)-(2t+4)=3(5t+5)-22

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Solution for 5(t-3)-(2t+4)=3(5t+5)-22 equation: 



5(t-3)-(2t+4)=3(5t+5)-22

We move all terms to the left:

5(t-3)-(2t+4)-(3(5t+5)-22)=0

We multiply parentheses

5t-(2t+4)-(3(5t+5)-22)-15=0

We get rid of parentheses

5t-2t-(3(5t+5)-22)-4-15=0



We calculate terms in parentheses: -(3(5t+5)-22), so:

3(5t+5)-22

We multiply parentheses

15t+15-22

We add all the numbers together, and all the variables

15t-7

Back to the equation:

-(15t-7)



We add all the numbers together, and all the variables

3t-(15t-7)-19=0

We get rid of parentheses

3t-15t+7-19=0

We add all the numbers together, and all the variables

-12t-12=0

We move all terms containing t to the left, all other terms to the right

-12t=12

t=12/-12

t=-1

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