-2(3-1k)+4=2(2k+5)

Solution for -2(3-1k)+4=2(2k+5) equation:

-2(3-1k)+4=2(2k+5)

We move all terms to the left:

-2(3-1k)+4-(2(2k+5))=0

We add all the numbers together, and all the variables

-2(-1k+3)-(2(2k+5))+4=0

We multiply parentheses

2k-(2(2k+5))-6+4=0


We calculate terms in parentheses: -(2(2k+5)), so:

2(2k+5)

We multiply parentheses

4k+10

Back to the equation:

-(4k+10)


We add all the numbers together, and all the variables

2k-(4k+10)-2=0

We get rid of parentheses

2k-4k-10-2=0

We add all the numbers together, and all the variables

-2k-12=0

We move all terms containing k to the left, all other terms to the right

-2k=12

k=12/-2

k=-6