5(2-c)=10(2c-4)-6(3

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Solution for 5(2-c)=10(2c-4)-6(3 equation: 



5(2-c)=10(2c-4)-6(3

We move all terms to the left:

5(2-c)-(10(2c-4)-6(3)=0

We add all the numbers together, and all the variables

5(-1c+2)-(10(2c-4)-63=0

We multiply parentheses

-5c-(10(2c-4)-63+10=0

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