-2(2y-3)+6y=-2(y+2)

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Solution for -2(2y-3)+6y=-2(y+2) equation:



-2(2y-3)+6y=-2(y+2)
We move all terms to the left:
-2(2y-3)+6y-(-2(y+2))=0
We add all the numbers together, and all the variables
6y-2(2y-3)-(-2(y+2))=0
We multiply parentheses
6y-4y-(-2(y+2))+6=0
We calculate terms in parentheses: -(-2(y+2)), so:
-2(y+2)
We multiply parentheses
-2y-4
Back to the equation:
-(-2y-4)
We add all the numbers together, and all the variables
2y-(-2y-4)+6=0
We get rid of parentheses
2y+2y+4+6=0
We add all the numbers together, and all the variables
4y+10=0
We move all terms containing y to the left, all other terms to the right
4y=-10
y=-10/4
y=-2+1/2

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