(1/2)(x-1)+3x=2(x+2)

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Solution for (1/2)(x-1)+3x=2(x+2) equation: 



(1/2)(x-1)+3x=2(x+2)

We move all terms to the left:

(1/2)(x-1)+3x-(2(x+2))=0



Domain of the equation: 2)(x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(x-1)+3x-(2(x+2))=0

We add all the numbers together, and all the variables

3x+(+1/2)(x-1)-(2(x+2))=0

We multiply parentheses ..

(+x^2+1/2*-1)+3x-(2(x+2))=0

We multiply all the terms by the denominator


(+x^2+1+3x*2*-1)-((2(x+2)))*2*-1)=0

We add all the numbers together, and all the variables

(+x^2+1+3x*2*-1)-((2(x+2)))*2*=0

We get rid of parentheses

x^2+3x*2*-((2(x+2)))*2*+1-1=0

We add all the numbers together, and all the variables

x^2+3x*2*-((2(x+2)))*2*=0

Wy multiply elements

x^2+6x^2-((2(x+2)))*2*=0

We add all the numbers together, and all the variables

7x^2-((2(x+2)))*2*=0

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