-2(-7y+6)-8y=2(y-2)-2

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Solution for -2(-7y+6)-8y=2(y-2)-2 equation:



-2(-7y+6)-8y=2(y-2)-2
We move all terms to the left:
-2(-7y+6)-8y-(2(y-2)-2)=0
We add all the numbers together, and all the variables
-8y-2(-7y+6)-(2(y-2)-2)=0
We multiply parentheses
-8y+14y-(2(y-2)-2)-12=0
We calculate terms in parentheses: -(2(y-2)-2), so:
2(y-2)-2
We multiply parentheses
2y-4-2
We add all the numbers together, and all the variables
2y-6
Back to the equation:
-(2y-6)
We add all the numbers together, and all the variables
6y-(2y-6)-12=0
We get rid of parentheses
6y-2y+6-12=0
We add all the numbers together, and all the variables
4y-6=0
We move all terms containing y to the left, all other terms to the right
4y=6
y=6/4
y=1+1/2

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