4y-1+y+37=8y+40-5y

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Solution for 4y-1+y+37=8y+40-5y equation: 



4y-1+y+37=8y+40-5y

We move all terms to the left:

4y-1+y+37-(8y+40-5y)=0

We add all the numbers together, and all the variables

4y+y-(3y+40)-1+37=0

We add all the numbers together, and all the variables

5y-(3y+40)+36=0

We get rid of parentheses

5y-3y-40+36=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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