-2(-4b-3)-4b=-6(10b-10)+10b

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Solution for -2(-4b-3)-4b=-6(10b-10)+10b equation: 



-2(-4b-3)-4b=-6(10b-10)+10b

We move all terms to the left:

-2(-4b-3)-4b-(-6(10b-10)+10b)=0

We add all the numbers together, and all the variables

-4b-2(-4b-3)-(-6(10b-10)+10b)=0

We multiply parentheses

-4b+8b-(-6(10b-10)+10b)+6=0



We calculate terms in parentheses: -(-6(10b-10)+10b), so:

-6(10b-10)+10b

We add all the numbers together, and all the variables

10b-6(10b-10)

We multiply parentheses

10b-60b+60

We add all the numbers together, and all the variables

-50b+60

Back to the equation:

-(-50b+60)



We add all the numbers together, and all the variables

4b-(-50b+60)+6=0

We get rid of parentheses

4b+50b-60+6=0

We add all the numbers together, and all the variables

54b-54=0

We move all terms containing b to the left, all other terms to the right

54b=54

b=54/54

b=1

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