(2f+1/2f)*f=f

Solution for (2f+1/2f)*f=f equation:

(2f+1/2f)*f=f

We move all terms to the left:

(2f+1/2f)*f-(f)=0


Domain of the equation: 2f)*f!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

(+2f+1/2f)*f-f=0

We add all the numbers together, and all the variables

-1f+(+2f+1/2f)*f=0

We multiply parentheses

2f^2+f^2-1f=0

We add all the numbers together, and all the variables

3f^2-1f=0

a = 3; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·3·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*3}=\frac{0}{6}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*3}=\frac{2}{6}
=1/3
$