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-1x(x-3)+6x=12+6x
We move all terms to the left:
-1x(x-3)+6x-(12+6x)=0
We add all the numbers together, and all the variables
-1x(x-3)+6x-(6x+12)=0
We add all the numbers together, and all the variables
6x-1x(x-3)-(6x+12)=0
We multiply parentheses
-x^2+6x+3x-(6x+12)=0
We get rid of parentheses
-x^2+6x+3x-6x-12=0
We add all the numbers together, and all the variables
-1x^2+3x-12=0
a = -1; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·(-1)·(-12)
Δ = -39
Delta is less than zero, so there is no solution for the equation
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