2(x-3)+3(2x-4)=(4x+1)-3(4x-1)

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Solution for 2(x-3)+3(2x-4)=(4x+1)-3(4x-1) equation: 



2(x-3)+3(2x-4)=(4x+1)-3(4x-1)

We move all terms to the left:

2(x-3)+3(2x-4)-((4x+1)-3(4x-1))=0

We multiply parentheses

2x+6x-((4x+1)-3(4x-1))-6-12=0



We calculate terms in parentheses: -((4x+1)-3(4x-1)), so:

(4x+1)-3(4x-1)

We multiply parentheses

(4x+1)-12x+3

We get rid of parentheses

4x-12x+1+3

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We add all the numbers together, and all the variables

8x-(-8x+4)-18=0

We get rid of parentheses

8x+8x-4-18=0

We add all the numbers together, and all the variables

16x-22=0

We move all terms containing x to the left, all other terms to the right

16x=22

x=22/16

x=1+3/8

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