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-1=3x(x-2)
We move all terms to the left:
-1-(3x(x-2))=0
We calculate terms in parentheses: -(3x(x-2)), so:We get rid of parentheses
3x(x-2)
We multiply parentheses
3x^2-6x
Back to the equation:
-(3x^2-6x)
-3x^2+6x-1=0
a = -3; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-3)·(-1)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{6}}{2*-3}=\frac{-6-2\sqrt{6}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{6}}{2*-3}=\frac{-6+2\sqrt{6}}{-6} $
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