-1=3(y-2)+2y

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Solution for -1=3(y-2)+2y equation: 



-1=3(y-2)+2y

We move all terms to the left:

-1-(3(y-2)+2y)=0



We calculate terms in parentheses: -(3(y-2)+2y), so:

3(y-2)+2y

We add all the numbers together, and all the variables

2y+3(y-2)

We multiply parentheses

2y+3y-6

We add all the numbers together, and all the variables

5y-6

Back to the equation:

-(5y-6)



We get rid of parentheses

-5y+6-1=0

We add all the numbers together, and all the variables

-5y+5=0

We move all terms containing y to the left, all other terms to the right

-5y=-5

y=-5/-5

y=1

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