-17(x+3)+6(4x-3)=6(x+3)+10

Solution for -17(x+3)+6(4x-3)=6(x+3)+10 equation:

-17(x+3)+6(4x-3)=6(x+3)+10

We move all terms to the left:

-17(x+3)+6(4x-3)-(6(x+3)+10)=0

We multiply parentheses

-17x+24x-(6(x+3)+10)-51-18=0


We calculate terms in parentheses: -(6(x+3)+10), so:

6(x+3)+10

We multiply parentheses

6x+18+10

We add all the numbers together, and all the variables

6x+28

Back to the equation:

-(6x+28)


We add all the numbers together, and all the variables

7x-(6x+28)-69=0

We get rid of parentheses

7x-6x-28-69=0

We add all the numbers together, and all the variables

x-97=0

We move all terms containing x to the left, all other terms to the right

x=97