-16x(2x-2)=-128

Solution for -16x(2x-2)=-128 equation:

-16x(2x-2)=-128

We move all terms to the left:

-16x(2x-2)-(-128)=0

We add all the numbers together, and all the variables

-16x(2x-2)+128=0

We multiply parentheses

-32x^2+32x+128=0

a = -32; b = 32; c = +128;
Δ = b2-4ac
Δ = 322-4·(-32)·128
Δ = 17408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17408}=\sqrt{1024*17}=\sqrt{1024}*\sqrt{17}=32\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32\sqrt{17}}{2*-32}=\frac{-32-32\sqrt{17}}{-64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32\sqrt{17}}{2*-32}=\frac{-32+32\sqrt{17}}{-64}
$