1+3n=4+3(n+0-1)

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Solution for 1+3n=4+3(n+0-1) equation:



1+3n=4+3(n+0-1)
We move all terms to the left:
1+3n-(4+3(n+0-1))=0
We add all the numbers together, and all the variables
3n-(4+3(n-1))+1=0
We calculate terms in parentheses: -(4+3(n-1)), so:
4+3(n-1)
determiningTheFunctionDomain 3(n-1)+4
We multiply parentheses
3n-3+4
We add all the numbers together, and all the variables
3n+1
Back to the equation:
-(3n+1)
We get rid of parentheses
3n-3n-1+1=0
We add all the numbers together, and all the variables
=0
n=0/1
n=0

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