-16=4(x-3)+3(2-x)

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Solution for -16=4(x-3)+3(2-x) equation: 



-16=4(x-3)+3(2-x)

We move all terms to the left:

-16-(4(x-3)+3(2-x))=0

We add all the numbers together, and all the variables

-(4(x-3)+3(-1x+2))-16=0



We calculate terms in parentheses: -(4(x-3)+3(-1x+2)), so:

4(x-3)+3(-1x+2)

We multiply parentheses

4x-3x-12+6

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We get rid of parentheses

-x+6-16=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10

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