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-15+50=-5x(x+1)
We move all terms to the left:
-15+50-(-5x(x+1))=0
We add all the numbers together, and all the variables
-(-5x(x+1))+35=0
We calculate terms in parentheses: -(-5x(x+1)), so:We get rid of parentheses
-5x(x+1)
We multiply parentheses
-5x^2-5x
Back to the equation:
-(-5x^2-5x)
5x^2+5x+35=0
a = 5; b = 5; c = +35;
Δ = b2-4ac
Δ = 52-4·5·35
Δ = -675
Delta is less than zero, so there is no solution for the equation
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