3(y+5)=9y+45

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Solution for 3(y+5)=9y+45 equation: 



3(y+5)=9y+45

We move all terms to the left:

3(y+5)-(9y+45)=0

We multiply parentheses

3y-(9y+45)+15=0

We get rid of parentheses

3y-9y-45+15=0

We add all the numbers together, and all the variables

-6y-30=0

We move all terms containing y to the left, all other terms to the right

-6y=30

y=30/-6

y=-5

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