-14-3(x+10)=7(2x+4)+x

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Solution for -14-3(x+10)=7(2x+4)+x equation: 



-14-3(x+10)=7(2x+4)+x

We move all terms to the left:

-14-3(x+10)-(7(2x+4)+x)=0

We multiply parentheses

-3x-(7(2x+4)+x)-30-14=0



We calculate terms in parentheses: -(7(2x+4)+x), so:

7(2x+4)+x

We add all the numbers together, and all the variables

x+7(2x+4)

We multiply parentheses

x+14x+28

We add all the numbers together, and all the variables

15x+28

Back to the equation:

-(15x+28)



We add all the numbers together, and all the variables

-3x-(15x+28)-44=0

We get rid of parentheses

-3x-15x-28-44=0

We add all the numbers together, and all the variables

-18x-72=0

We move all terms containing x to the left, all other terms to the right

-18x=72

x=72/-18

x=-4

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