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5(2x+5)=11(x-3)
We move all terms to the left:
5(2x+5)-(11(x-3))=0
We multiply parentheses
10x-(11(x-3))+25=0
We calculate terms in parentheses: -(11(x-3)), so:We get rid of parentheses
11(x-3)
We multiply parentheses
11x-33
Back to the equation:
-(11x-33)
10x-11x+33+25=0
We add all the numbers together, and all the variables
-1x+58=0
We move all terms containing x to the left, all other terms to the right
-x=-58
x=-58/-1
x=+58
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