-12=2(v+2)+6v

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Solution for -12=2(v+2)+6v equation: 



-12=2(v+2)+6v

We move all terms to the left:

-12-(2(v+2)+6v)=0



We calculate terms in parentheses: -(2(v+2)+6v), so:

2(v+2)+6v

We add all the numbers together, and all the variables

6v+2(v+2)

We multiply parentheses

6v+2v+4

We add all the numbers together, and all the variables

8v+4

Back to the equation:

-(8v+4)



We get rid of parentheses

-8v-4-12=0

We add all the numbers together, and all the variables

-8v-16=0

We move all terms containing v to the left, all other terms to the right

-8v=16

v=16/-8

v=-2

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