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(3+5)2x^2-x=48
We move all terms to the left:
(3+5)2x^2-x-(48)=0
We add all the numbers together, and all the variables
82x^2-x-48=0
We add all the numbers together, and all the variables
82x^2-1x-48=0
a = 82; b = -1; c = -48;
Δ = b2-4ac
Δ = -12-4·82·(-48)
Δ = 15745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{15745}}{2*82}=\frac{1-\sqrt{15745}}{164} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{15745}}{2*82}=\frac{1+\sqrt{15745}}{164} $
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