3(t-4)+6=3(2t-6)

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Solution for 3(t-4)+6=3(2t-6) equation: 



3(t-4)+6=3(2t-6)

We move all terms to the left:

3(t-4)+6-(3(2t-6))=0

We multiply parentheses

3t-(3(2t-6))-12+6=0



We calculate terms in parentheses: -(3(2t-6)), so:

3(2t-6)

We multiply parentheses

6t-18

Back to the equation:

-(6t-18)



We add all the numbers together, and all the variables

3t-(6t-18)-6=0

We get rid of parentheses

3t-6t+18-6=0

We add all the numbers together, and all the variables

-3t+12=0

We move all terms containing t to the left, all other terms to the right

-3t=-12

t=-12/-3

t=+4

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