-124+41/7x=-9-1/8x

Solution for -124+41/7x=-9-1/8x equation:

-124+41/7x=-9-1/8x

We move all terms to the left:

-124+41/7x-(-9-1/8x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

41/7x-(-1/8x-9)-124=0

We get rid of parentheses

41/7x+1/8x+9-124=0

We calculate fractions


328x/56x^2+7x/56x^2+9-124=0

We add all the numbers together, and all the variables

328x/56x^2+7x/56x^2-115=0

We multiply all the terms by the denominator


328x+7x-115*56x^2=0

We add all the numbers together, and all the variables

335x-115*56x^2=0

Wy multiply elements

-6440x^2+335x=0

a = -6440; b = 335; c = 0;
Δ = b2-4ac
Δ = 3352-4·(-6440)·0
Δ = 112225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{112225}=335$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(335)-335}{2*-6440}=\frac{-670}{-12880}
=67/1288
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(335)+335}{2*-6440}=\frac{0}{-12880}
=0
$